Question

compute the following


325C1

Answer 1

@wolf1728

Answer 2

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

Answer 3

I think the answer to the combination question is 6*5*4*3*2*1
which I think is 720

Answer 4

MY MISTAKE
6*5*4*3

Answer 5

COMPUTE THE FOLLOWING;
8c8

Answer 6

and c means combination?

Answer 7

YES

Answer 8

CN U HELP ?

Answer 9

@jim_thompson5910

Answer 10

Looking at wikipedia to find exactly how to do that :-)

Answer 11

ty

Answer 12

In general

n C n = 1

where n is any integer

Answer 13

*any positive integer

Answer 14

this is because there is only one way to have a group of n people (drawn from a total pool of n people) and order doesn't matter

Answer 15

so what this means is that you replace n with 8 to get

8 C 8 = 1

Answer 16

10c4 * 4c2 = ? @jim_thompson5910

Answer 17

or basically it is asking how many k items can be chosen from a group of n

Answer 18

10c4 means how many ways can k things (4) be selected from n things (10).
combinations = n! / (n-k)! * k!
10c4 = 10*9*8*7*6*5*4*3*2*1 / 6*5*4*3*2*1 * (4*3*2*1)
= 10*9*8*7 / 4*3*2*1
= 10*3*7
=210

4c2 = 4! / 2! * 2!
4c2 = 3*2*1
= 6

so, 10c4 * 4c2 =
210*6
= 1,260

Answer 19

TY so much

Answer 20

u r welcome