Question

Can someone double check:
1.lim x-->0 : x^2+2x/x^4

cancel x^2 and x^4 = 2x/x^2 direct substitute, lim DNE or 0

2. Direct substitution: lim x-->pi/2 : (2e^xsinx) = pi/2

Answer 1

@SithsAndGiggles ?

Answer 2

\[\lim_{x\to0}\frac{x^2+2x}{x^4}=\lim_{x\to0}\frac{x+2}{x^3}\]
The limit doesn't exist.

For the second limit, directly substituting gives you
\[\lim_{x\to\pi/2}2e^x\sin x=2e^{\pi/2}\sin \frac{\pi}{2}=2e^{\pi/2}\]

Answer 3

for 2. I put in 2e^pi/2 but it was the incorrect answer. my other choices are 0,1, or pi/2 @SithsAndGiggles

Answer 4

Not sure what to tell you: http://www.wolframalpha.com/input/?i=Limit%5B2*Exp%5Bx%5D*Sin%5Bx%5D%2Cx-%3Epi%2F2%5D

Maybe you mean a different function?

Answer 5

I'll choose it again, thanks

Answer 6

It's correct, my bad