Question

find lim as x approaches infinite of 5+radicalx/ 3x+1 if it exist

Answer 1

\[\lim_{x\to \infty}\frac{5+\sqrt{x}}{3x+1}\]?

Answer 2

if that is it, the answer is zero, because the numerator has degree \(\frac{1}{2}\) and the denominator has degree \(1\)
imagine \(x=1,000,000\)
the numerator would be \(1005\) and the denominator would be \(3000001\)

Answer 3

see i was confused by the part '' if it exists" i thought they wanted me to check from right and left of infinity

Answer 4

there is only one way to get to positive infinity

Answer 5

Thanks a lot

Answer 6

yw

Answer 7

use continuity to evaluate lim as x approaches pie of sin(x+ sinx)

Answer 8

since this is a continuous function (composition of continuous functions is continuous) you job it only to replace \(x\) by \(\pi\) and compute
\[\sin(\pi+\sin(\pi))\]

Answer 9

Wow thanks once again

Answer 10

yw