okay
three equations, if they are independent equations , we can do this. lets see....
oh, we will do something hot with eqn 2 and 3. Multiply second equation by -2 so you have -2x-2y-6z=8. Then you are going to add this with eqn 3. you will get -z= 1. this means that z= -1.
and it turns out actually that there is no solution to this problem... :( because the three equations are not independent.
Look at the 1st two columns of your equations (in x and y), looks like every x is a constant multiply of y. If any two rows or columns are functions of each other, then the system of equations is not independent. Also, the determinant of these equations is zero, which validates the observation made.
what do you get when you take the second equation form the first three times?
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