Question

which of the following is true for the rational function f(X)=x^2-x-6/x-8

Answer 1

factor out the top, you get (x-3)(x+2) and bottom is x-8.

Answer 2

you realize that bottom cannever be 0 which means x-8 cannot be 0--> x cannot be 8.

Answer 3

#1 You must learn to WRITE these clearly. If you mean \(\dfrac{x^{2} - x - 6}{x-8}\), you must write not as you have written, but f(x) = (x^2-x-6)/(x-8). It is NOT a small thing and I am not just being picky. You should have studied the Order of Operations.

Answer 4

Also, notice how I changed f(X) to f(x). Normally, it is considered bad form to confuse upper and lower case.

Answer 5

Now, we'll need those comments so we can tell which are true and which are false.

Answer 6

A) the vertical asymptote is y=-8 B) The vertical asymptote is x=8 C) there is a hole in the graph at x=8 D) The zeroes of the function are -3 and 2.

Answer 7

Okay, how do you find Vertical Asymptotes?

Answer 8

i forgot

Answer 9

What is the value of the function when there is a vertical asymptote?

In other words, if there is a vertical asymptote at x = 7, what is the value of f(7)?

Answer 10

not sure on this one tkhunny sorry.

Answer 11

You have to throw me something. What is an asymptote all about? What do they look like? What do they do? Are they friendly?

Seriously, I can write you a book on the subject, but if you already have a book and you're just not using it, why would my book be of any value to you. You have to show me you have SOME exposure to this material or I cannot help you in this forum.