Please help me understand the problem 2 + 4 * 3^x =4, solve for x ?
\[2+4(3^{x})= 4\] Is that correct?
yes
I see 4(3^x) = 2, but I don't know how to bring down x, log perhaps???
Get the exponential part by itself as much as possible first. So now you would divide by 4 to get 3^x by itself.
ok! thats an idea 3^x = 2/3
Should be (1/2) on the otherside xD
ugh you are right Psymom, so can I do x log 3 = log 1/2 ???
*Psymon
Well, it would have to be calculator work. So yeah, you'd divide both sides by ln3
x = (log1/2)log 3 ??? I'm running the calc now
If a take log on one side, don't I also apply that to the other side?
Well, you started with this before the ln: \[3^{x} = \frac{ 1 }{ 2 }\] Then we took the natural log of both sides to help get the x out of the exponent position: \[xln(3) = \ln(\frac{ 1 }{ 2 })\] Now I would divide both sides by ln(3) to get: \[x = \frac{ \ln(\frac{ 1 }{ 2 }) }{ \ln(3) }\approx -.691\]
I hate myself
you both have been helpful! We're all here to learn and help. Thank you both and thanks Psymon, I was getting the idea but my computation was wrong. Thanks for the correction!
Yep, np ^_^
:-)
Giving an erroneous calculation is not helpful!
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