Can someone help me understand this? 2(-3a^8b)^3
think of the stuff inside the bracket as x.So the question is 2x^3
now exponentiation has higher priority tham multiplication. so first you gotta do x^3
ok... so the power of 3 operates on everything inside the brackets the power of a power law is \[(x^a)^b = x^{a \times b}\] you need to apply this law as well as \[2 \times (-3)^3\]
I ended up getting -6^(3)2a^(11)2b^(3)
wait up..
first tell me what you get by doing x^3
I am pretty confused right now..
:D.ok i'll help you out
not quite.... the expanded form is \[2 \times (-3)^3 \times (a^8)^3 \times (b^1)^3\] apply the index law for power of a power, shown above... and evaluate the rest
@nkswizzle did you get it mate?
@dlearner struggling.. if you can solve it by step by step maybe I can get it :[.
right.. (-3)^3=-27 (a^8)^3 = a^24 b^3 =b^3 :) now write it all together and multiply by tw
@nkswizzle what did you get :)
@dlearner I got 2 (-27)(a^24)(b^3) !
put the two withem mate :)
@dlearner Now I got -54 2a^24 2b^3
it was simple was't it? :)
hey yo>>> multiply the 2 only once @nkswizzle . its common to all
@dlearner ah thanks ! It was just a bit confusing with the 2a^24 and the 2b^3 :p
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