Okay 2 chem questions.
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?
Answer

3.88 kg

32.3 g

3.88 g

32.3 kg

Question

Okay 2 chem questions.
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?
Answer
		
3.88 kg
		
32.3 g
		
3.88 g
		
32.3 kg

anonymous · Answer

Would someone help me set up the equation to the first one?

anonymous · Answer

daigram isnt appearing an error

anonymous · Answer

Let me try again

anonymous · Answer

Solve this equation for mass...
q = mcΔT

anonymous · Answer

diagram is not needed for calculation

anonymous · Answer

For the second one the question is based off of the diagram.
Thank you for the equation I am wondering how to set it up properly.
Would q be 138 kj - what would M be?

anonymous · Answer

I have set up warily the equation for the first one..
138 =  5*(7.11)triangleT

anonymous · Answer

I feel like I'm missing something.