Question

A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?
Answer

3.88 kg

32.3 g

3.88 g

32.3 kg

I need help setting up this equation.
q = mcΔT
138 = 5*(7.11)triangleT

i have this but I feel like its wrong

Answer 1

First you need to convert kilojoules to joules
138*1000=138000 J
And you must convert kelvins to celsius
298-273=25 C 303-273=30
Now 30-25= 5
So your equation is now

138000=x * 7.11 * 5
138000=35.6x
So
x=3876g
or
x=3.88kg D

Answer 2

Woops I mean A haha

Answer 3

Thanks so much for your help!