Question

please help me solve x

Answer 1

\[4+\frac{ 3 }{ x-3 }=-\frac{ 1 }{ x-2 }\]

Answer 2

4(x-2)(x-3)+3(x-2)=-1(x-3)
4x^2-20x+24+3x-6=-x+3
4x^2-16x+21=0

Answer 3

you should be able to get it from there

Answer 4

do i just factor \[4x ^{2}-16x+21\]

Answer 5

yes

Answer 6

oh i see. thank you!

Answer 7

i'm still very confused on this

Answer 8

can someone go step by step for me please?

Answer 9

Ill tell you how I started. First you have to get rid of the denominators. So multiply both sides by (x-3) then multiply both sides by (x-2)

Answer 10

ok.

Answer 11

Then you write out the whole equation (that just means solve until the parenthesis are gone)
you're left with this 4x^2-20x+24+3x-6=-x+3

Answer 12

next you simplify.

4x^2 -17x+18=-x+3

then you move the stuff on the right side of the equation to the left side of the equation

4x^2-16x+15=0

Answer 13

I just realized I had a typo on my original answer. sorry, I'm doing my own math at the same time. haha

Answer 14

haha yeah. that's alright. I just did the work and I got the answer you just posted :)

Answer 15

can I factor that?

Answer 16

wait, I think I can

Answer 17

Yes, they are (2x-5)(2x-3)

Answer 18

so x= 5/2 and 3/2

Answer 19

cool! i understood it! thank you so much!

Answer 20

No problem! :)