easy chem q:

A solution of Mg(OH)2 has a hydroxide concentration of 6.04 x 10^-2 M. What is the pOH of this solution?

pOH = 1.22

pOH = 12.78

pOH = 1.52

pOH = 12.48

Question

easy chem q:


A solution of Mg(OH)2 has a hydroxide concentration of 6.04 x 10^-2 M. What is the pOH of this solution?
		
pOH = 1.22
		
pOH = 12.78
		
pOH = 1.52
		
pOH = 12.48

kainui · Answer

Whenever you see a little p like that, it really means -log. For example:

$$pH=-\log_{10}(H)$$

Also, they write plain H or OH but really what they mean to write is: [H+] or [OH-] which means specifically the concentration of hydrogen or hydroxide in grams per mole (g/mol) which is exactly the same unit as molarity, for the record.

$$1 \frac{ gram }{ mole }=1M$$

so just take the negative log of that OH concentration to find the pOH, easy peasy.

anonymous · Answer

I tried taking the negative log and I kept getting the wrong answer.

kainui · Answer

What did you get as the answer? I got 1.22

anonymous · Answer

I did -log(6.04x10^-2)

anonymous · Answer

is that right?

kainui · Answer

Yeah, that's what I did.

anonymous · Answer

Now I got the right answer, thank you so much!

kainui · Answer

Cool no problem