For the given statement Pn, write the statements P1, Pk, and Pk+1. (2 points) 2 + 4 + 6 + . . . + 2n = n(n+1)
Ok, so I believe here they are stating that the statement \(P_n\) represents the sum of even numbers up to \(2n\)
so, to find \(P_1\) we set \(n=1\) which means it will be the sum of even numbers up to \(2*1=2\) and its value will be \(1(1+1)=2\). Does that make sense?
yes it does
but do i put p1=2
yes, you could write it as:\[P_1=1(1+1)=2\]
because:\[P_n=n(n+1)\]
so, to find \(P_k\), just set \(n=k\)
so then 2=k
no, it would be more like:\[P_k=2+4+...+2k=k(k+1)\]
similarly, for \(P_{k+1}\) just set \(n=k+1\)
i.e. where ever you see an \(n\) just replace it with \(k+1\)
so then ( k + 1) × ( k + 2)
perfect! well done! :)
thanks
yw :)
Join our real-time social learning platform and learn together with your friends!