For the given statement Pn, write the statements P1, Pk, and Pk+1.
(2 points)
2 + 4 + 6 + . . . + 2n = n(n+1)
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OpenStudy (asnaseer):
Ok, so I believe here they are stating that the statement \(P_n\) represents the sum of even numbers up to \(2n\)
OpenStudy (asnaseer):
so, to find \(P_1\) we set \(n=1\) which means it will be the sum of even numbers up to \(2*1=2\) and its value will be \(1(1+1)=2\).
Does that make sense?
OpenStudy (anonymous):
yes it does
OpenStudy (anonymous):
but do i put p1=2
OpenStudy (asnaseer):
yes, you could write it as:\[P_1=1(1+1)=2\]
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OpenStudy (asnaseer):
because:\[P_n=n(n+1)\]
OpenStudy (asnaseer):
so, to find \(P_k\), just set \(n=k\)
OpenStudy (anonymous):
so then 2=k
OpenStudy (asnaseer):
no, it would be more like:\[P_k=2+4+...+2k=k(k+1)\]
OpenStudy (asnaseer):
similarly, for \(P_{k+1}\) just set \(n=k+1\)
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OpenStudy (asnaseer):
i.e. where ever you see an \(n\) just replace it with \(k+1\)