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Mathematics 9 Online
OpenStudy (anonymous):

laplace transform of f(t)=kt?

OpenStudy (anonymous):

assuming k is some number , then we would have to look for laplace transform of the form \[t^{n}f(t)\] then f(t) would be just any constant k right ?

OpenStudy (anonymous):

so if f(t) is a function which have Laplce transform F(s) the laplace of the whole thing you can find by applying this formula \[(-1)^{n}\frac{ d^{n}F(s) }{ ds^{n} }\]

OpenStudy (anonymous):

well lap.tr. off k is k/s, know for kt?

OpenStudy (anonymous):

yes laplace transform of k is k/s so acording to the formula i wrote above you need to look for first derivative of k/s (since n=1 because t is of degree 1 )

OpenStudy (anonymous):

so you would have \[(-1)^{1}\frac{ d }{ ds }(\frac{ k }{ s })=-1(-\frac{ k }{ s^2 })=\frac{ k }{ s^{2} }\]

OpenStudy (anonymous):

im not familiar with this formula, I'm using f(t)e^(-st)

OpenStudy (anonymous):

oh you need to find it by definition ?

OpenStudy (anonymous):

with this formula :\[\int\limits_{0}^{\infty}{e^{-st}f(t)dt}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok so since it is integral with bounds from 0 to infinity we need to rewrite it with limit going to infinity , you familiar with solving this kind of integrals ?

OpenStudy (anonymous):

I'm getting lost simplifying

OpenStudy (anonymous):

did you try solving the integral ?

OpenStudy (anonymous):

you are getting lost simplifying what ?

OpenStudy (anonymous):

sorry had to go take a test

OpenStudy (anonymous):

its cool dont worry , you needed help not me so ... i hope the test went well xD

OpenStudy (anonymous):

i breezed throughout all the questions except the last one (only 5 questions) need an A to pass the test, the laplace transform is an extra credit project which I'm doing to help me hopefully pass

OpenStudy (anonymous):

oh well make sure u do that laplace transform its easy ^^

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