Question

Factor the polynomial: 12k^2-36k+27

Answer 1

divide though by 3

Answer 2

3(4k^2-12k+9)
3(4k^2-6k-6k+9)
(2k(2-3)-3(2k-3)
(2k-3)(2k-3)

Answer 3

like 3(4k^2-12k+9) ??

Answer 4

ughh please change your name and pic ASAP ...haha

Answer 5

i can change my user? @dumbcow

Answer 6

@dumbcow best response lol

Answer 7

-.-

Answer 8

Nah i don't hate him bro, he gives a s**t load of money to charities.

Answer 9

thank you, so is my answer correct?

Answer 10

@supraron

Answer 11

Idk but mine is

Answer 12

the one i gave you is the right answer

Answer 13

help!!

Answer 14

Are you serious i gave you the answer lol

Answer 15

@supraron but I need explanation

Answer 16

Find the GCF (greatest common whatever you know what i mean right ) (lol)
then divide every numbers by this GCF and put the new numbers in parentheses.
2nd step, find 2 numbers that, when added are equal to -12 and when multiplied are equal to 36 (you do first term times last term to get 36)
So i found -6 and -6.
Now rewrite the equation
3(4k^2-6k-6k+9) don't put the +36 keep the 9
Now Factor by 2 terms inside the parentheses you can get rid of the 3 outside.
2k(2k-3)-3(2k-3)
Finally put the terms outside the parentheses and the terms inside the parentheses together
(2k-3) (2k-3)
GET IT>>?