Question

Use the substitution formula to evaluate the integral.
3t/(5+t^2)^4 dt [-1,0]

Answer 1

\[\int_{-1}^{0}\frac{3t}{(5+t^2)^4}dt\]right?

Answer 2

Yes!

Answer 3

Can you help me with the steps @Loser66

Answer 4

let u = 5+t^2 --> du =?

Answer 5

3t dt?

Answer 6

nope, du = 2t dt, but I need 3t dt, right? so?

Answer 7

Oh! Derivative of U my bad, it would be 2t

Answer 8

So? lol

Answer 9

ok, i give you one more step: du = 2t dt --> \(\frac {du}{2} = tdt\) right? but I need 3t dt , so, I time 3 both sides. I get \[\frac{3}{2}du = 3t dt\] OK??? got it? can step up?

Answer 10

hmm?

Answer 11

what hmmm? don't understand? why ? quite clear,