Please and Thank you! "Evaluate each of the following. In each case, explain your thinking."
I'm not looking for the answers, just some guidance. Besides I did a few already...
a. Part I: √3/2 b. Part I: 5 = c Part II: don't I just use the equation given to me?\[\sin (\tan^{-1} (\frac{ 4 }{ 3 }))\]
Use the triangle given to you. What the question is asking is what does sin x = using a triangle where tanx = 4/3? So using that triangle, just find the sin of it :3
OH!!! gotcha \[\sin = \frac{ opp }{ hyp }\]
Yeah xD
\[\sin = \frac{ 4 }{ 5 }\] Is that my answer?
Yep.
Final answer?
Well, it wants the hypotenuse, so that was 5. Now we have sin(theta) = 4/5. you probably should actually find theta from the looks of the question
Geez, amazing how many of the people asking questions on here are all people using this apex whatever.
Yes! It is crazy :P
Some questions ive seen 4 times I think, lol. So you dont still use apex, do ya?
Not exactly? I used to though. I can still log on, and check out the different assignments. I want to be ready for my first class "Intro to College Math"
So asking people about certain formulas and identities should help! Also I got:\[\theta = 53.13º\]
Lol, that works xD And that seems right to me. But yeah, intro to college math? I would think trig is above the intro level xD
Oh. So then I was doing all of this for NO REASON!?!?!?! NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
But actually, its okay. I still need to keep my mind sharp!
Well......At my college, we have math 124 (college algebra). Which is at the same level ish as math 126 (precalculus 1). Then we have math 127 (precalculus 2/trigonometry). So at my school, intro to college math would be 1-2 levels below trig.
oh okay! Well, I only have to take one course for Math (for my major)
Ah, nice, lol. I still have 4 more x_x It sucks, if it werent for a schedule conflict id be able to take calc 3 this semester.
Oh dang! I don't think I'd ever be able to do that.. What is your major?
Well, I have an associates in japanese and im working on a math major. Im attending a 4-year uni for the first time starting the 27th where Im taking more Japanese classes for a minor and starting on my bachelors in math. I still have 5 more classes at the community college level first, though, but since I have a high enough math already, I can start taking some 300 level classes.
JAPANESE? I bow down man! And 300 level? I'm still at 100, maybe less... So inadequate
まだ日本語を学んでいるですが、もうたくさん習いました
Eh, my japanese isnt that great, but I know some, haha. But yeah, I guess. All 300 level means is Ive done enough calculus, haha.
I have no clue what that is... I've taken elementary Spanish, one year of high school Mandarin, and one year of Tagalog/Ilocano
Still know NOTHING! :P
Lol, well after 4 semesters of Japanese I still feel like I know nothing xD My hearing is horrible, so I have no idea what people are sayign to me. but I know how to occasionally answer and such. I can't speak well either, haha. But I'm better than I thought I'd be if Im just typing or texting in Japanese, lol.
Why is your name Psymon? Psy is a famous rapper from South Korea, but you probs knew that! And it sounds like "simon"
Sorry, I was just always wondering!
Yeah, it does sound like Simon, lol. I've had that pseudonym thingy since I was maybe 10 or 11, lol. So something that has stuck. If I don't use Psymon, I use PsymonSays
I see! Oh and we kinda never finished the problem? Letter a, Part II?
To solve the problem, find the the angle whose value is rt3/2? That problem?
Wait... what?
Im not exactly sure which question xD I see the arccos(cos-pi/6) one
...find the angle in the interval [0,π] whose cosine is √3/2? Yes that one. Sorry, I was a bit distracted
Well, easy if you know your unit circle xD It gives you the answer with the whole arccos(cos-pi/6). Since arccos and cos are inverses, they just cancel out and leave -pi/6. Only thing to know is that since cosx is an even function, cos(-pi/6) is the same as cospi/6.
Doesn't cos(-π/6) already equal √3/2?
Yep. But it wants an angle between 0 and pi xD
30º angle!
Lol, yep xD But all I meant is that any cosine angle that is negative is the same value when its positive. cos(-pi/6) = cos(pi/6)
I understand that part... And both equal 30º.
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