Question

graph the equation with a diameter that has endpoints at (-3,4) and (5,-2)

Answer 1

@mary.rojas

Answer 2

what would the center be?

Answer 3

its doesnt say and i dont know how to find it

Answer 4

its in the middle of the two points

Answer 5

given points (a,b),(c,d)
\[midpoint = (\frac{a+c}{2},\frac{b+d}{2})\]

Answer 6

so whats the midpoint?

Answer 7

1.1?

Answer 8

im confused about the question

Answer 9

is this the equation of a circle?

Answer 10

how did you get 1.1?

Answer 11

you shuold get a ordered pair

Answer 12

??????I'm so long

Answer 13

lost*

Answer 14

It should be a circle.
Centre = midpoint of the 2 given endpoints = ((5 - 3) / 2 , (4 - 2) / 2)) = (1 , 1)
Radius = length of 1 endpoint to centre = sqrt ((5 - 1)^2 + (-2 - 1)^2) = 5 units
(x - 1)^2 + (y - 1)^2 = 5^2
x^2 - 2x + 1 + y^2 - 2y + 1 = 25
x^2 + y^2 - 2x - 2y - 23 = 0

Answer 15

you should get it to the standard form of a circle by "completing the square"
\[x^2+y^2-2x-2y-23=0\\(x^2-2x)+(y^2-2y)-23=0\\((x-1)^2-1
)+((y-1)^2-1)-23=0\\(x-1)^2+(y-1)^2=5^2\]