For what values of c is the curve y = c/(x+1) tangent to the line through the points (0,3) and (5, -2)?
help me please :)
have you found the equation of the line through those two points?
is it y = -x + 3? this is for the equation for the tangent line. am I correct?
@UnkleRhaukus
yes that is the line through the two points
what should I do next?
@UnkleRhaukus
when do the equations y = c/(x+1) y = -x + 3 meet?
i think you have to find the value for c which makes one solution to those equations
ohh, so I just need to equate those two and solve for c? am I correct?
well equate them yes, c/(x+1) = -x + 3 what so can simply it to
c = (-x + 3)(x+1) is that it?
Why did my teacher got the derivative of y = c/(x+1)? He didn't finish the solution, so I don't know if i'm right.
you want there to be exactly one solution, you'll have to expand the brackets and complete the square,
oh, we can use derivatives?
Our topic is differential calculus , so I think I need to use derivatives here. yes
oh right sorry, i was thinking of a different approach.
well can you take the derivative of y = c/(x+1)
\[\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v^2}\]
I got y' = -c/(x+1)^2
thats right
what should I do next?
This is were I'm stuck :)
i dont really understand this question
ohhh
I think the next step is -c/(x+1)^2 = -1 because the derivative of y = c/(x+1) is it's tangent line
yeah, .,
How about this, using discriminants? y = c / (x + 1) y = -x + 3 -x + 3 = c / (x + 1) (-x + 3)(x + 1) = c -x^2 + 2x + 3 = c x^2 - 2x - 3 = -c x^2 - 2x + c - 3 = 0 b^2 - 4ac = 0 (-2)^2 - 4(1)(c - 3) = 0 4 - 4c + 12 = 0 4c = 16 c = 4
@TURITW Why is it that b^2 - 4ac = 0 ?
b^2 - 4ac > 0 means 2 real and distinct roots. b^2 - 4ac = 0 means 2 real and equal roots. b^2 - 4ac < 0 means 2 complex roots.
Why do you need to have equal roots?
Equal roots means tangent, because the curve needs to touch the line once
Why is it that equal roots means tangent? I'm sorry if it's a dumb question. :)
@TURITW
Equal roots means same coordinates, so it means it only cuts the line once, example, It cuts the line at (1 , 1) (just a random coordinates) only.
Thanks, I'll just show my teacher two different solutions. I'll just ask for the correct answer. :)
Thanks to both of you. :)
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