Can anyone solve this? lim (x^2-x+1)/(x-sin(x)), x→0+. The answer is ∞. Please give me a step-wise solution.
first substitute 0 in place of x. you'd get \[\left[ \frac{ 1 }{0}\right] =\frac{ + }{ }\infty\] you see that x goes to zero from right side, so substitute a number which is near zero from right side, for instance 0,1 to determine the sign of that infinity. after doing that: \[\frac{ 0,91 }{0,1-0,0017 }\] you know that this value will be positive so the limit is + infinity
Can it be simplified first? And after that we can subsitute 0?
It won't give you anything cause x goes to zero, even if you factored x , you'd get sinx/x goes to one but upstairs 1/0 which you don't know if it's + or - infinity
okay! i got it. thanks for help.
yw:)
you are maths student?
Join our real-time social learning platform and learn together with your friends!