Question

Explain two ways you could evaluate (f + g)(2). Explain two ways you could evaluate (f + g)(2). @Mathematics

Answer 1

well, you could do f(2), get an answer, then add it to g(2). Or you can combine all the like terms and combine f(x) and g(x), then plug in 2 and solve. Both get the same answer.

Ex.
\[f(x)=3x ^{2}+4\]
\[g(x) = 5x ^{2}-6x+1\]
If I evaluate f(2) I get 3(2)^2 + 4 = 16
If I evaluate g(2) I get 5(2)^2 - 6(2) + 1 = 9. Add the two together andI get 25.

Now if I do it the other way and combine the two functions first.
\[f(x)+g(x) = 8x ^{2}-6x+5\] Now I'll evaluate (f+g)(2)
8(2)^2 - 6(2) + 5 = 32 - 12 + 5 = 25. So you can see both give the same answer :3

Answer 2

i need help with another problem

Answer 3

Does (f - g)(x) result in the same function as (g - f)(x)?

Answer 4

(f + g)(2)
f(2)+g(2)

I find this the easiest ^

Answer 5

Yes @aliballa1 It's same.

Answer 6

Wouldn't they just be opposites? One would be just the negative of the other.

Answer 7

Oh yea..

Answer 8

What is a good strategy for being successful with word problems?