Question

q⁷ x q x q⁻⁹ x q⁻³

A.) q⁻⁶
B.) 1/q⁴
C.) q⁻³
D.) 1/q³

Answer 1

b

Answer 2

Thanks.

Answer 3

welcome again.. ;)

Answer 4

Add all the powers because it is multiplied!
q^7+1-9-3
q-4
Thus the answer is B) 1/q^4
q^0-4 = q^-4

Answer 5

@benetsaidso add all the powers,where its (-) subract it.

Answer 6

As the basis of the elements is the same (here : q), you can use the form q^x*q^y = q(x+y). This means that you can reduce the problem to an easy summation of powers over q. This comes down to 7+1-9_3 = -4.

Remember that a negative exponent translates in 1/exponent, so q^-4 = 1/(q^4), which gives answer b).

Answer 7

Thanks again guys (: