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Chemistry 22 Online
OpenStudy (anonymous):

Which of the following is an example of an endothermic process?

OpenStudy (chmvijay):

where are examples LOL

OpenStudy (anonymous):

a chocolate bar melting in hot car a package of fruit freezing in a freezer burning gasoline in a combustion engine moisture forming on a glass of iced water

OpenStudy (anonymous):

First one

OpenStudy (anonymous):

Meliting process is Endothermic

OpenStudy (anonymous):

Melting*

OpenStudy (anonymous):

ok why wouldn't it be the last one

OpenStudy (anonymous):

@chmvijay will explain you

OpenStudy (anonymous):

The process of melting is endothermic because you are adding heat (or energy) to the object. When you add heat or energy to an object it begins to melt , Which tells you the object has reached its melting point or the temperature that the object melts at. endothermic is adding heat or energy (ENdothermic means ENtering) exothermic is removing heat or energy (EXothermic means EXiting). Conversely, the process of freezing is exothermic.

OpenStudy (anonymous):

oh ok thank you so much

OpenStudy (chmvijay):

yaaa fourth one is not right bcoz the gas is getting converted to liquid on the surface of iced water :) conversion of H2O(G)---->H2O (L) is exothermic and H2O(L) ----> H2O(Gas) is endothermic

OpenStudy (anonymous):

Using the equations and enthalpy values provided, which mathematical expression can be used to determine the unknown enthalpy change of the decomposition of propane? 3 C + 3 O2 yields 3 CO2 deltaH =-1182 kJ 4 H2 + 2 O2 yields 4 H2O deltaH = -1144 kJ C3H8 + 5 O2 yields 3 CO2 + 4 H2O deltaH = -2222 kJ C3H8 yields 3 C + 4 H2 deltaH = ? kJ (-1182) - [(-2222) + (-1144)] (-2222) - [(-1182) + (-1144)] (-1182) +(-1144) + (-2222) (-2222) + (-1182) - (-1144)

OpenStudy (chmvijay):

ask question in new dialogue box let all see it :)

OpenStudy (anonymous):

I'm new how do i post questions to a new dialogue box?

OpenStudy (chmvijay):

just close this question first and then u post new one u have to wait for some time :)

OpenStudy (anonymous):

ok thank you :)

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