Question

Express answer in exact form.

Find the area of one segment formed by a square with sides of 6" inscribed in a circle.

(Hint: use the ratio of 1:1:√2 to find the radius of the circle.

Answer 1

\[diameter DB=\sqrt{6^{2}+6^{2}}=6\sqrt{2}\]
\[radius r=3\sqrt{2}\]
\[area of one segment =\frac{ \pi r ^{2} }{ 4 }-\frac{ 1 }{ 2 }*r*r=\frac{\left( \pi-2 \right)r ^{2} }{ 4 }\]
plug the value of r and solve.

Answer 2

my answer has to be in something divided by something pi- something

Answer 3

surji gave you the answer

Answer 4

how do I find r tho

Answer 5

he told you.

but you can figure it out yourself


how long is the diagonal ? you can use 45-45-90 triangles or you can use
pythagoras a^2 + b^2 = c^2