Question

Algebra II Question, writing it below

Answer 1

How would I found the equation of this graph?

Answer 2

@terenzreignz

Answer 3

Have to write the equation as: y=a(x-h)^2+k, anyone willing to guide me through this?

Answer 4

I am not sure I remember these things , but I think a is the distance between the focus and the vertex which is 3 and you have the vertex (h,k) = (3,0) , just substitute with these values in the equation you have written.
I hope I'm right

Answer 5

@litchlani @hartnn @ganeshie8

Answer 6

I'm not on the list

Answer 7

@live10000000 now u r :P I was just linking some people who usually help out that r on right now :)

Answer 8

lol ur funny

Answer 9

thx :D I didn't know u wanted 2 help :P This is like my last question that i'm stuck on -_- then after this i'm going 2 this yearbook company and back 2 more algebra 2 4 me :P

Answer 10

Sorry I really don't know
is this a mutiple choice Question

Answer 11

it's ok lol and no u have 2 write it :P

Answer 12

Sorry then
I wish I could of helped
♥

Answer 13

it's ok :D

Answer 14

By hope someone can help u

Answer 15

"General" equation of a parabola (which faces sideways) is
\[\Large (y-k)^2 = 4p(x-h)\]
Where (h,k) is the vertex. Thankfully, the vertex is (as per the graph) (0,0)

So it is reduced to
\[\Large y^2 = 4px\]

Now, the p here is the 'directed distance' FROM your vertex TO the focus.
That means it's positive if the focus is to the right of the vertex, and negative if it's to the left.

In other words, if your parabola opens to the right, p is positive, and it's negative if the parabola opens to the left.

In this case, it opens to the right, and the focus is 3 units away from the vertex.
Then p = 3 for this case, which gives us the equation:
\[\Large y^2 = 4(3)x\]\[\LARGE \color{blue}{y^2= 12x}\]