A sphere is constructed of two concentric pieces. The inner part is a solid sphere of radius 10.0 cm made of a material with density 4000 kg/m3. The outer part is a spherical shell with inner radius 10.0 cm and outer radius 20.0 cm. The outer shell has a density 9000 kg/m3. a) find mass of this sphere b) what is the average density of this sphere
a) \[M=\rho_1\frac{ 4 }{ 3}\pi r_1^3 + \rho_2 \frac{4}{3}\pi (r_2^3-r_1^3)\]
b) \[\rho_{average}=\frac{ allMass }{ all Volume }\]
so a) is 2.1467 x 10 ^11
a) 280,5 kg b)8374,8 kg/m^3
nvm, i forgot to add the 4/3 in the second part
what do you divde 280648943.7 by to get 280.6?
we work in SI units , so you have to also convert cm to m
yeah i got 2.80 x 10^11
it's impossible check out again
0,1^3= 0,001
got it
so all of mass is 281, how do you find all of volume?
and average density is by definition all the mass divided by all the volume so this volume is simply 4/3 pi *(0,2)^3
its the volume of sphere with outer radius. It's all the volume where all the mass is in
8388
I found 8375 but it's close to it
i keep getting 8385
I substituted 280,5 for mass you 281 so it's correct
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