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Physics 14 Online
OpenStudy (summersnow8):

A sphere is constructed of two concentric pieces. The inner part is a solid sphere of radius 10.0 cm made of a material with density 4000 kg/m3. The outer part is a spherical shell with inner radius 10.0 cm and outer radius 20.0 cm. The outer shell has a density 9000 kg/m3. a) find mass of this sphere b) what is the average density of this sphere

OpenStudy (fifciol):

a) \[M=\rho_1\frac{ 4 }{ 3}\pi r_1^3 + \rho_2 \frac{4}{3}\pi (r_2^3-r_1^3)\]

OpenStudy (fifciol):

b) \[\rho_{average}=\frac{ allMass }{ all Volume }\]

OpenStudy (summersnow8):

so a) is 2.1467 x 10 ^11

OpenStudy (fifciol):

a) 280,5 kg b)8374,8 kg/m^3

OpenStudy (summersnow8):

nvm, i forgot to add the 4/3 in the second part

OpenStudy (summersnow8):

what do you divde 280648943.7 by to get 280.6?

OpenStudy (fifciol):

we work in SI units , so you have to also convert cm to m

OpenStudy (summersnow8):

yeah i got 2.80 x 10^11

OpenStudy (fifciol):

it's impossible check out again

OpenStudy (fifciol):

0,1^3= 0,001

OpenStudy (summersnow8):

got it

OpenStudy (summersnow8):

so all of mass is 281, how do you find all of volume?

OpenStudy (fifciol):

and average density is by definition all the mass divided by all the volume so this volume is simply 4/3 pi *(0,2)^3

OpenStudy (fifciol):

its the volume of sphere with outer radius. It's all the volume where all the mass is in

OpenStudy (summersnow8):

8388

OpenStudy (fifciol):

I found 8375 but it's close to it

OpenStudy (summersnow8):

i keep getting 8385

OpenStudy (fifciol):

I substituted 280,5 for mass you 281 so it's correct

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