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Mathematics 20 Online
OpenStudy (anonymous):

Is this right? (question below)

OpenStudy (anonymous):

\[\frac{ 1 }{2 } (x+10)>-(x+1)\]

OpenStudy (jdoe0001):

depends on what you mean by "right"

OpenStudy (anonymous):

This is what I came up with \[\frac{ 1 }{ 2 }x+5>-1x\]

OpenStudy (anonymous):

I'm working on what I already have. Give me a few seconds

OpenStudy (anonymous):

\[\frac{ 1 }{ 2}>-6x\]

OpenStudy (anonymous):

\[\frac{ 1 }{ 2 } /-6\]

OpenStudy (jdoe0001):

hmm, keep in mind that a/b * c => ac/b

OpenStudy (anonymous):

So I came up with x=-12

OpenStudy (anonymous):

Is that right?

OpenStudy (jdoe0001):

\(\bf \cfrac{ 1 }{2 } >-(x+1) \implies \cfrac{(x+10)}{2} > -(x+1)\\ (x+10)> 2\times-(x+1) \implies x+10> -2x-2\)

OpenStudy (jdoe0001):

hmm, typos :( one sec

OpenStudy (anonymous):

No problem :)

OpenStudy (jdoe0001):

\(\bf \cfrac{ 1 }{2 }(x+10) >-(x+1) \implies \cfrac{(x+10)}{2} > -(x+1)\\ (x+10)> 2\times-(x+1) \implies x+10> -2x-2\)

OpenStudy (jdoe0001):

so, it's not 14 though

OpenStudy (jdoe0001):

I mean, -12

OpenStudy (anonymous):

Thanks! I had a slight (ok more than slight) error! Thanks! \(\Huge\ddot\smile\)

OpenStudy (jdoe0001):

yw

OpenStudy (ybarrap):

$$\tt \frac{1}{2}(x+10)>-(x+1)\\ x+10>-2x-2\\ x+2x>-2 -10\\ 3x>-12\\ \text{Answer:}~x>-4$$

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