Question

perform the operation and simplify: (3+2i/2-3i)

Answer 1

\[\frac{(3+2i)}{(2-3i)}*\frac{(2+3i)}{(2+3i)}\]
this will eliminate "i" from denominator
remember i^2 = -1

Answer 2

I don't understand how to factor this out because I thought I had to multiple 3i by both 2 and the other 3i

Answer 3

my teacher said the answer is I. I just don't know how to find it

Answer 4

just distribute
\[\rightarrow \frac{6+13i+6i^{2}}{4-9i^{2}}\]

Answer 5

\[=\frac{13i}{13} = i\]

Answer 6

how did 4-9i^2 go to 13?

Answer 7

i^2 = -1

4-(-9) = 4+9 = 13

Answer 8

oh yeah you just told me that. thank you!

Answer 9

yw