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Geometry 8 Online
OpenStudy (anonymous):

Please help its only one question i will fan u and give u metal http://assets.openstudy.com/updates/attachments/520ac9d1e4b08984debd11b9-hkimn-1376438765386-kuku.png

OpenStudy (anonymous):

what question?

OpenStudy (anonymous):

Out of my depth sweetie, ask zzr0ck3r, he's good at math. :)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

the diagonals of a square are congruent... Thus \[\left( 2x-1 \right)+\left( 3y+5 \right)=4x-y+1\]

OpenStudy (anonymous):

ok but how how do i solve it

OpenStudy (anonymous):

i get the equation but dont know how to find the variables

OpenStudy (anonymous):

@pgpilot326

OpenStudy (anonymous):

so 2x + 3y +4 = x - y + 1 so x + 4y = -3

OpenStudy (anonymous):

but you also have the the fact that the diagonals of a square bisect each other... so 2x-1 = 3y + 5 => 2x - 3y = 6 now you have a system of linear equations. Do you know how to solve these? x + 4y = -3 2x - 3y = 6

OpenStudy (anonymous):

no i dont to be honest can you help

OpenStudy (anonymous):

yep... we can solve this by elimination -2x + 4y = -3 2x - 3y = 6 and add... y = 3 and plug it in... 2x - 3(3) = 6 => 2x - 9 = 6 => 2x = 15 => x = 15/2 so let's check in the original equations... 2x-1 => 2(15/2) - 1 = 15 - 1 = 14 3y + 5 = 3(3) + 5 = 9 + 5 = 14 and finally 4x - y + 1 = 4(15/2) -(3) + 1 = 30 - 3 + 1 = 28 so it all works out... Whew!

OpenStudy (anonymous):

wow man ur like extremelt good in math

OpenStudy (anonymous):

hey, sorry I forgot a 4 ... it should have been 2x + 3y + 4 = 4x - y + 1 I forgot the 4 in front of the x on the right hand side. my apologies. but I put it back in the above equations to solve. and I checked the solutions so were good.

OpenStudy (anonymous):

i've been at it a little while... hehe

OpenStudy (anonymous):

its ok man thank you

OpenStudy (anonymous):

i voted u as best response

OpenStudy (anonymous):

did you post your new question? Thanks! and you're welcome!

OpenStudy (anonymous):

i have 2 other questions but they dont need work out can u help\

OpenStudy (anonymous):

yeah, just post them.

OpenStudy (anonymous):

OpenStudy (anonymous):

this \

OpenStudy (anonymous):

what do you know about a rhombus?

OpenStudy (anonymous):

diagonals are perpendicular and all sides are congruent thats all i know

OpenStudy (anonymous):

diagonals are perpendicular bisectors of each other and yes, all sides are congruent. but there's something a little more obvious than that... can you tell me what it is?

OpenStudy (anonymous):

right angless

OpenStudy (anonymous):

opp. angles are cong

OpenStudy (anonymous):

not right angles (except in a square) and yes opp angles are congruent. something much more obvious... how many sides?

OpenStudy (anonymous):

4 sides

OpenStudy (anonymous):

yes... and what the interior angle sum of a quadrilateral?

OpenStudy (anonymous):

not quiet sure sir.

OpenStudy (anonymous):

better yet, what's the interior angle sum of a triangle?

OpenStudy (anonymous):

all angles are equal to 180

OpenStudy (anonymous):

the angles sum to 180. so 26 +m<1 +m<2 = 180 and 26 = m<1, right? so m<2 = 180 - 2*26 = 180 - 52 =...

OpenStudy (anonymous):

in the first one. I've got to get going now, sorry. you have all the ammo you need to conquer this. best of luck!!!

OpenStudy (anonymous):

ok thank u mannn ur the bestt

OpenStudy (anonymous):

you're welcome and thank you, too!

OpenStudy (anonymous):

do u have to goo lol

OpenStudy (anonymous):

yeah... to a friend's for dinner

OpenStudy (anonymous):

o ok have a good dinner my friendddd

OpenStudy (anonymous):

thanks, see ya next time!

OpenStudy (anonymous):

u too

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