Question

Please can someone help me. I have to get this done. I'm sick and its kinda hard to focus when ur trying to feel better. my teacher even said this is one of the hardest modules.

Answer 1

What is it?

Answer 2

Subtract and simplify: The quantity 5 x plus 6, all over the binomial x squared minus 1, end quantity, minus the quantity 1 over the binomial x squared minus 1, end quantity.

Answer 3

gabgurl, where did you get that? I can't see the problem.

Answer 4

flvs. that is the problem but in word form

Answer 5

I'm in flvs right now actually........

Answer 6

\[\frac{ 5x+6 }{ x ^{2}-1}-\frac{ 1 }{ x ^{2}-1 }\]

Answer 7

really. what subject and whos ur teacher

Answer 8

OH, I'm sorry I didn't see that you weren't two different people.....

Answer 9

ok hold on ill try

Answer 10

since the denominator is the same then:\[\frac{ 5(x+1) }{ (x-1)(x+1) }=\frac{ 5 }{ x-1 }\]

Answer 11

the first one u wrote ahmad is the one

Answer 12

wow!

Answer 13

did I do anything wrong @gabgurl ?

Answer 14

no

Answer 15

so now you have the answer ;)

Answer 16

really?

Answer 17

later gabgurl, nice to know I'm not the only FLVS girl here! :)

Answer 18

LOL! byeee

Answer 19

ahmad do u mind helping me with a couple more? @Ahmad1

Answer 20

go ahead

Answer 21

ok thanks

Answer 22

Add and simplify: the quantity 4 over the binomial x minus 7, end quantity, plus the quantity 1 over the binomial x minus 3, end quantity

Answer 23

multiply by (x-7) and (x-3) to find the LCD you get :\[\frac{ 4(x-3)-(x-7) }{ (x-7)(x-3) }\]

Answer 24

im still a little confused

Answer 25

sorry im a pain in the butt

Answer 26

\[\frac{ 4x-12+x-7 }{ (x-3)(x-7) }=\frac{ 5x-19 }{ (x-3)(x-7) }\] I hope that's right

Answer 27

no no it's my bad @gabgurl I put - instead of +

Answer 28

yes that is! thank u

Answer 29

thank u(: @Ahmad1

Answer 30

you are so welcome @gabgurl :)

Answer 31

:)