Question

Find the polynomial f(x) that has the roots of –3, 5 of multiplicity 2.

Answer 1

anyone? please

Answer 2

no one?

Answer 3

multiplicity two means that the term for 5 appears twice. Just multiply out (x+3)(x-5)(x-5)

Answer 4

So what would the polynomial f(x) be that has those roots and that multiplicity?

Answer 5

multiply the three I gave you: (x+3)(x-5) becomes x^2-2x-15. Multiply this by (x-5): (x^2-2x-15)(x-5) = x^3-7^2-5x+75. It makes sense that since there are three components, the polynomial is of degree 3.

Answer 6

So the polynomial that I need is x^3-7^2-5x+75 or x^3-7x^2-5x+75?

Answer 7

Nvm i got it thanks so much!

Answer 8

no problem man.