Mathematics
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OpenStudy (anonymous):
Eliminate the parameter.
x = 5 cos t, y = 5 sin t
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OpenStudy (anonymous):
Same as before, what would you do this time?
jimthompson5910 (jim_thompson5910):
hint: square both sides and add the equations together
jimthompson5910 (jim_thompson5910):
why do this? because you can take advantage of the fact that
sin^2(x) + cos^2(x) = 1
OpenStudy (anonymous):
so it would be x^2=25t?
jimthompson5910 (jim_thompson5910):
no not quite
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OpenStudy (anonymous):
Think of your pathagoriean identities. And remember to factor out any constants...
jimthompson5910 (jim_thompson5910):
x = 5*cos(t)
x^2 = (5*cos(t))^2
x^2 = (5^2)*(cos(t))^2
x^2 = 25cos^2(t)
jimthompson5910 (jim_thompson5910):
do the same for y
OpenStudy (anonymous):
so for y it would be
y = 5*sin(t)
y^2 = (5*sin(t))^2
y^2 = (5^2)*(sin(t))^2
y^2 = 25sin^2(t)
jimthompson5910 (jim_thompson5910):
yep
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jimthompson5910 (jim_thompson5910):
now add the two equations to get
x^2 + y^2 = 25cos^2(t) + 25sin^2(t)
jimthompson5910 (jim_thompson5910):
see where this is going?
OpenStudy (anonymous):
x^2 + y^2 = 25[cos^2 (t) + sin^2(t) ] = 25
OpenStudy (anonymous):
so the answer would be what you put? @deepconcept
jimthompson5910 (jim_thompson5910):
that's not the final answer, but that's leading up to it
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OpenStudy (anonymous):
final answer is x^2 + y^2 = 25
as cos^2(t) + sin^2 (t) = 1
OpenStudy (anonymous):
Thank you guys so much!!!
jimthompson5910 (jim_thompson5910):
you're welcome