Question

Eliminate the parameter.

x = t2 + 2, y = t2 - 4

Answer 1

i legit just had this

Answer 2

isolate the t in the first equation.

Answer 3

so t=sq rt x?

Answer 4

t = sqrt x/2?

Answer 5

\[t = \sqrt{x-2}\]

Answer 6

t=sqrt x -2

Answer 7

now plug in the equation you just go into the "t"" in the "y=" equation

Answer 8

so then y = sqrt x-2- 4

Answer 9

the second equation is supposed to look like, right?
\[y=t^2-4\]

Answer 10

yes

Answer 11

y = (sqrt x-2)^2 - 4

Answer 12

yes, but since the square cacels out the square root, you will end up with
y=x-2-4

Answer 13

oh, so y = x-6

Answer 14

yup, so did that help?

Answer 15

yes! thank you

Answer 16

no problem!

Answer 17

x = t2 + 2, y = t2 - 4

Really? Square roots and substitution?

\(t^{2} = x-2\)
\(t^{2} = y+4\)

\(x-2 = y+4\)