Question

factor:
see below>>>>>

Answer 1

\[7wk(2-3)+4m(3-z)\]

Answer 2

Is it (3-2)?

Answer 3

sorry z-3

Answer 4

@Psymon

Answer 5

z-3 where? o_O

Answer 6

7wk(z-3)+4m(3-z)

Answer 7

I got (-7wk+4m)(3-z)

Answer 8

(7wk-4m)(3-z) ???????

Answer 9

both negative??

Answer 10

So you chose to put the order as 3-z. Alright, so let's see. I need to factor out a negative in the left parenthesis if I want it to also be 3-z. This means I would have:
\[-7wk(3-z)+4m(3-z)\]

Answer 11

So that means we just have:
\[(4m-7wk)(3-z)\]

Answer 12

the problem is 7wk(z-3)+4m(3-z)

Answer 13

I ended up with (7wk-4m)(z-3)

Answer 14

sorry I will have to double question the problem before I post next time

Answer 15

Well let's do it that way if it's z-3 then. I did it as if it were 3-z xD

Answer 16

double check, I mean

Answer 17

Yep, if you have one parentheis be z-3 instead, then what you have is correct.

Answer 18

first part of problem has it (z-3) and the second part has it (3-z)

Answer 19

ok thank you for the help Psymon :)

Answer 20

Well, all I mean is you can choose if you want one of your factors to be z-3 or 3-z, it just depends on which one you factor the negative out of xD

Answer 21

ok got it

Answer 22

\[8z ^{9}y ^{5}x ^{15}-72z ^{10}y ^{8}x ^{5}\]

Answer 23

we need to find greatest common factor correct?

Answer 24

Work with each itty bit at a time. Greatest common factor of numbers, then z's, then y's, then x's

Answer 25

I got 4

Answer 26

4 goes into 8 and 72

Answer 27

8 also goes into 8 and 72 : )

Answer 28

no it would be 8 correct

Answer 29

yes ok

Answer 30

Okay, so we got the 8 ripped out, now lets find the biggest x, y, and z we can rip out.

Answer 31

\[z ^{10}y ^{8}x ^{15}\]

Answer 32

Well, those are all too big xD We cannot take out those powers from BOTH terms.

Answer 33

\[8z ^{9}y ^{5}x ^{5} ( )( )\]

Answer 34

do I subtract exponents?

Answer 35

Well, you wouldn't have two groups of parenthesis, just:
\[8z ^{9}y ^{5}x ^{5}(something - something)\]

Answer 36

So yeah, you would subtract exponents to see what's left inside of the parenthesis :3

Answer 37

ok

Answer 38

\[8z ^{9}y ^{5}x ^{5}(x ^{10}-9zy ^{3})\]

Answer 39

do you agree??

Answer 40

Yep, looks good :3