Question

Relative maximum? g(x)=7/(x^2+5) . last question. Thanks for any help!

Answer 1

assuming you know how to work with derivatives, you would derive it to get

g(x)=7/(x^2+5)

g(x)=7*(x^2+5)^(-1)

g ' (x)=7*(-1)*(x^2+5)^(-2) * d/dx[x^2+5)

g ' (x)=-7/( (x^2+5)^2 ) * (2x)

g ' (x)=-14x/( (x^2+5)^2 )

Answer 2

then you'd set the derivative equal to zero and solve for x

once you figure out that x value, plug that x value back into g(x) to find the max value

Answer 3

So should I set it up as -14x/((x^2+5)^2)=0 ? @jim_thompson5910