Question

@AkashdeepDeb @mialovesyou03

Answer 1

can u respond with numbers please instead of words i understand better that way

Answer 2

@AkashdeepDeb

Answer 3

Try doing this by the hit and trial method!
Try putting random values like 1,2,-1 etc.
And if f(x) turns out to be 0 then x-1 , x-2 , x+1 etc. respectively would be the factors!
In the equation f(1) = 0! :D
Thus x-1 would be a factor!
And then divide the cubic polynomial with the factor x-1 and get a quadratic equation!
And I am sure you know how to factorize Quadratic equations! :)
For the verification part, put all the factor values that you get in f(x) and all will result in f(x) = 0! And thus you'd prove the factorization! :)
I hope you get that! :)

Answer 4

look, in part 1 u gotta find all possible values . so all possible values are the factors of the constant i.e. 4
therefore factors of 4 = 1,2,4,-1,-2,-4 so these all are the possible roots

now in second part you can input these values
and in third part i think after doin both steps above you will know which of them is factor soyou can write three such factors take for example the 2,3 4 are factors. then factorisation would be (x-2)(x-3)(x-4)

Answer 5

got it ?

Answer 6

can you show me in numbers how im suppose to do that i understand better @pratyush5

Answer 7

allryt whcih part 2nd part or third ?

Answer 8

part 1,2 and 3

Answer 9

1. the factors of the given polynomial can only be the factors of the constant. here constant is 4 so factor are

4= 1,2,4,-1,-2,-4

so now you input any of them in the polynomial for example lets put -2