Convert to polar coordinates: x^2-3y+y^2=0

Question

psymon · Answer

We just need to remember our conversions:
$$r ^{2} = x ^{2} + y ^{2}$$
$$x = rcos \theta   $$
$$y = rsin \theta  $$
Using those 3 conversions, think you can find out what to do from there?

anonymous · Answer

I think so.  r^2 would be set equal to 3y so r=sqrt(3y), correct?

anonymous · Answer

Ok that still doesn't seem right, help out with next step?  I can see that is is a circle, and that only r needs to be solved for.  I'm not seeing the next step

blockcolder · Answer

No x's and y's should be left in the end, and there's still a y in r=sqrt(3y).

dumbcow · Answer

you need r in terms of theta
$$r^{2}-3r \sin \theta = 0$$
$$r = 3 \sin \theta$$