Question

Convert to polar coordinates: x^2-3y+y^2=0

Answer 1

We just need to remember our conversions:
\[r ^{2} = x ^{2} + y ^{2}\]
\[x = rcos \theta \]
\[y = rsin \theta \]
Using those 3 conversions, think you can find out what to do from there?

Answer 2

I think so. r^2 would be set equal to 3y so r=sqrt(3y), correct?

Answer 3

Ok that still doesn't seem right, help out with next step? I can see that is is a circle, and that only r needs to be solved for. I'm not seeing the next step

Answer 4

No x's and y's should be left in the end, and there's still a y in r=sqrt(3y).

Answer 5

you need r in terms of theta
\[r^{2}-3r \sin \theta = 0\]
\[r = 3 \sin \theta\]