Question

is the answer c for the question below

Answer 1

Which is the simplified form of 16 times a to the eighth power all over 12 times a squared.?

4a6

4a4

4 over 3. a4

4 over 3. a6

Answer 2

so you have

16a^8
-------
12a^2

Answer 3

First simplify the 16 and the 12 (both are divisible by 4) so what do you get?

Answer 4

1. 4 4
2. 4 3

Answer 5

ok so now you have

4a^8
-----
3a^2

Answer 6

now you need to simplify the variable with the exponent as follows:
you have a^8 and a^2 that is equal to a^(8-2) which is ????

Answer 7

a^6

Answer 8

ok so you have the answer 4/3 a^6

Answer 9

thanks can you help with more

Answer 10

sure

Answer 11

Which number equals the square root of 192.?

8 the square root of 3.

3 the square root of 8.

4 the square root of 3.

8 the square root of 2.

Answer 12

ok so you have \(\sqrt{192}\)

Answer 13

which is the same as \(\sqrt{64.3}\) correct ?

Answer 14

64 times 3 = 192

Answer 15

ok

Answer 16

so what is the \(\sqrt{64}\)

Answer 17

8

Answer 18

ok so you can take out the 8 and you have left 8\(\sqrt{3}\)

Answer 19

ok

Answer 20

hope you understand it :)

Answer 21

yep

What is the simplified form of the expression the square root of the quantity 16 times c to the fourth power. - the square root of c squared. + 3the square root of c squared. + the square root of the quantity 9 times c squared.?

4c2 + 5c

4c2 + 7c

8c2 + 5c

8c2 + 7c

Answer 22

so you have equation as follows:

\(\sqrt{16c^4}\) - \(\sqrt{c^2}\) + 3\(\sqrt{c^2}\) +\(\sqrt{9c^2}\)

is that correct ??

Answer 23

yes

Answer 24

ok first let see the definition of square root
A number that produces a specified quantity when multiplied by itself: "7 is a square root of 49".

Answer 25

so let solve first \(\sqrt{16c^4}\) what would that be ???

Answer 26

4c^4

Answer 27

ok , according to the definition square root is a number multiplies by itself
so let see 4 x 4 = 16 that is good by c^4 x c^4 = c^8
law of exponents a^x times a^y = a^(x+y)
so it would be (c^2 times c^2) = c^4 so it would be
4c^2 ??? understand

Answer 28

oh ok ya

Answer 29

so now what

Answer 30

so is the answer a

Answer 31

so you have 4c^2
now lets solve the other square roots, lets do \(\sqrt{c^2}\),what would that be ??

Answer 32

c^2

Answer 33

remember c^2 times c^2 = c^4, you need a multiple by itself that is c^2

Answer 34

ok sits now c^4

Answer 35

NO, the \(\sqrt{c^2}\) = \(\sqrt{c.c}\),

Answer 36

\(\sqrt{16}\) equals to \(\sqrt{4.4}\) that is why \(\sqrt{16}\) = 4
so what is the \(\sqrt{c^2}\) = ??

Answer 37

c

Answer 38

WONDERFUL, you are getting it

Answer 39

so you have

4c^2 -c + 3c - \(\sqrt{9c^2}\) now solve the last square root what is that equal to

Answer 40

I meant 4c^2 -c +3c + \(\sqrt{9c^2}\)

Answer 41

\(\sqrt{9c^2}\) = \(\sqrt{3.3.c.c}\)

Answer 42

ok

Answer 43

so what is that equal to ??

Answer 44

3c

Answer 45

great, now you have

4c^2 -c +3c + 3c now you combine like terms (do you know how to ?

Answer 46

9c^3

Answer 47

when you add variables, you can only combine the one with the same exponents, never combine variables with different exponents

Answer 48

4c^2+5c

Answer 49

so you have 4c^2 that is the only one that have an exponent of 2
CAN NOT COMBINE with nothing else stays as it is

no you have -c + 3c + 3c (all this variable are the same exponent of 1)
you can combine so you have -1 +3 +3 = +5

so the final answer is 4c^2 + 5

Answer 50

yes 5c

Answer 51

What is the product of 4the square root of 6. • 8the square root of 14.? Simplify if possible.

32the square root of 21.

32the square root of 42.

64the square root of 21.

64the square root of 42.

Answer 52

so you have 4\(\sqrt{6}\) x 8\(\sqrt{14}\)

Answer 53

ya

Answer 54

you can start by multiplying the digits outside so 4 x 8 = ??

Answer 55

32

Answer 56

ok now multiply what is inside the square root

Answer 57

84

Answer 58

great, so now you have

32\(\sqrt{84}\)

Answer 59

so that is the same as 32\(\sqrt{4.21}\) so what can you take out of the square ?

Answer 60

32

Answer 61

32 is out already, I mean from what is inside the square

Answer 62

21

Answer 63

you have 4 x 21 the only one that have a multiple by itself is the 4 ( 2 x 2) so you can take out the 2, now you have


32 x 2 \(\sqrt{21}\)

so 32 x 2 = 64 so it is 64 \(\sqrt{21}\)