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Mathematics 20 Online
OpenStudy (anonymous):

i need help with step 4 and 5 @ilfy214 @ivettef365 @amistre64

OpenStudy (anonymous):

OpenStudy (amistre64):

a composition is when one thing is "composed" (or built with) the other one ...

OpenStudy (amistre64):

f(g(x)) means that the function defined for f(x) is composed of (made with, built with) the function defined for g(x)

OpenStudy (anonymous):

thats what i put 4 5?

OpenStudy (anonymous):

put for 5?

OpenStudy (amistre64):

i just explained to you what a composite function means ... now its up to you to determine what your particular f(g(x)) equals when x=3 :/

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@ilfy214 can u help?

OpenStudy (anonymous):

i need help with 5 now

OpenStudy (anonymous):

@amistre64 explained what a composite function is.... "a composition is when one thing is "composed" (or built with) the other one ...f(g(x)) means that the function defined for f(x) is composed of (made with, built with) the function defined for g(x)" So yes for 4

OpenStudy (anonymous):

What is the equation you used for Part I and Part II and I guess Part III also??

OpenStudy (anonymous):

What is the function*

OpenStudy (anonymous):

Step 1 inches(x) = 12x converts feet to inches Step 2 feet(y) = 3y converts yards to feet Step 3 inches(feet(y)) = 12(3y) = 36y converts yards to inches.

OpenStudy (anonymous):

OKay... Well plug in x = 3! But I suggest you use minor changes for your formulas

OpenStudy (anonymous):

\[f(x) = 12x\]\[g(x) = 3x\]\[f(g(x)) = 36x\]

OpenStudy (anonymous):

oo what did i do wrong

OpenStudy (anonymous):

The first is fine! :) But the second and third don't work if there is no "x" to work with

OpenStudy (anonymous):

You can't plug in "x" when you only have a y

OpenStudy (anonymous):

sso what do i do

OpenStudy (anonymous):

if you really want to use "y", use it for the first equation, but it tells you to use "x"\[f(x) = 12\]\[f(y)=12y\]What do you do? Look at the equations I did before... Not in this comment

OpenStudy (anonymous):

12*3?

OpenStudy (anonymous):

Plug it in the last function HERE:\[f(y)=12y\]\[ g(x)=3x \]\[f(g(x))=12(3x)= 36x\]

OpenStudy (anonymous):

thats it?

OpenStudy (anonymous):

Nope! You have to plug in 3, and THEN thats it

OpenStudy (anonymous):

i thought we did

OpenStudy (anonymous):

3 is x?

OpenStudy (anonymous):

yes! 3 = x We didn't. There are two 3s in this function. The 3 for: g(x) = 3x And the 3 for : x = 3

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

so it would be 3(3) 12 (3)(3)=36(3)

OpenStudy (anonymous):

YES!!!!

OpenStudy (anonymous):

so what do i so now

OpenStudy (anonymous):

:D WOO-HOO!\[f(g(x)) = 12(3(3)) = 12(9) = ?\]

OpenStudy (anonymous):

You solve it

OpenStudy (anonymous):

can we restate everything we did for part 1,2,3,4 and 5 to make sure i have everything correct and its 108

OpenStudy (anonymous):

Okay! And correct!

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Part I:\[f(y)=12y\]OR\[f(x) = 12x\] Part II:\[g(x) = 3x\] Part III:\[f(g(x))=12(3x)\] Part IV: thats whatever you wrote! Part V:\[f(g(x)) = 12(3x) = 12(3(3)) = 12(9) = 108\] MAKES SENSE???

OpenStudy (anonymous):

yesssssss thank you:)

OpenStudy (anonymous):

No problem! Thats what you have right?

OpenStudy (anonymous):

yessss

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