i need help with step 4 and 5 @ilfy214 @ivettef365 @amistre64
a composition is when one thing is "composed" (or built with) the other one ...
f(g(x)) means that the function defined for f(x) is composed of (made with, built with) the function defined for g(x)
thats what i put 4 5?
put for 5?
i just explained to you what a composite function means ... now its up to you to determine what your particular f(g(x)) equals when x=3 :/
im confused
@amistre64
@ilfy214 can u help?
i need help with 5 now
@amistre64 explained what a composite function is.... "a composition is when one thing is "composed" (or built with) the other one ...f(g(x)) means that the function defined for f(x) is composed of (made with, built with) the function defined for g(x)" So yes for 4
What is the equation you used for Part I and Part II and I guess Part III also??
What is the function*
Step 1 inches(x) = 12x converts feet to inches Step 2 feet(y) = 3y converts yards to feet Step 3 inches(feet(y)) = 12(3y) = 36y converts yards to inches.
OKay... Well plug in x = 3! But I suggest you use minor changes for your formulas
\[f(x) = 12x\]\[g(x) = 3x\]\[f(g(x)) = 36x\]
oo what did i do wrong
The first is fine! :) But the second and third don't work if there is no "x" to work with
You can't plug in "x" when you only have a y
sso what do i do
if you really want to use "y", use it for the first equation, but it tells you to use "x"\[f(x) = 12\]\[f(y)=12y\]What do you do? Look at the equations I did before... Not in this comment
12*3?
Plug it in the last function HERE:\[f(y)=12y\]\[ g(x)=3x \]\[f(g(x))=12(3x)= 36x\]
thats it?
Nope! You have to plug in 3, and THEN thats it
i thought we did
3 is x?
yes! 3 = x We didn't. There are two 3s in this function. The 3 for: g(x) = 3x And the 3 for : x = 3
Does that make sense?
so it would be 3(3) 12 (3)(3)=36(3)
YES!!!!
so what do i so now
:D WOO-HOO!\[f(g(x)) = 12(3(3)) = 12(9) = ?\]
You solve it
can we restate everything we did for part 1,2,3,4 and 5 to make sure i have everything correct and its 108
Okay! And correct!
:)
Part I:\[f(y)=12y\]OR\[f(x) = 12x\] Part II:\[g(x) = 3x\] Part III:\[f(g(x))=12(3x)\] Part IV: thats whatever you wrote! Part V:\[f(g(x)) = 12(3x) = 12(3(3)) = 12(9) = 108\] MAKES SENSE???
yesssssss thank you:)
No problem! Thats what you have right?
yessss
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