find the slope-intercept form of the equation of the line passing through the point (-3,2) and parallel to the line with the equation 2x+y=7
You know what the slope intercept form is right?\[y = mx + b\]
Isolate the "y" variable on the left side by moving your "x" variable onto the right side
thanks!
Did you get it? I can check for you :)
Also, you're welcome!
i'm still lost
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yea, I get that, but then do I have to plug in (-3, 2) into the y= mx+b to find the other slope?
Not the slope. What is the equation you have right now?
we have to find the equation of the line parallel to 2x+y=7
and it must go through (-3,2)
I know that. But parallel lines have the same slope...
right, so 2/1is the slope
so you plug that in for m
So here is the initial line\[ 2x+y=7 \]\[y=7 -2x\] From the equation I gave you, what is the slope? Not +2/1
-2/1
no?
CORRECT!
so would the slope intercept form be\[y=-2x-4\]
wait no!
Since you're given a point that the line you're looking for will pass through, you can solve for b. Insert your points \[y = mx + b \]\[(+2) = -2(-3) + b\]\[2= 6 + b\]\[? = b \]
\[-4\]
Correct! Now plug in the results into your equation \[y = mx+b\]\[y = -2x -4\]So why did you doubt yourself?
thanks so much!
You're Welcome! :) Anytime
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