Question

which of the following are solutions to the equation
Check all that apply.
4x^2-12x+9=5

Answer 1

a.\[x=\frac{- \sqrt{5} +3}{ 2 }\]

Answer 2

B.\[x=\sqrt{4}-3\]

Answer 3

C.\[x=\frac{ \sqrt{5}+3 }{ 2 }\]

Answer 4

D.\[x=\sqrt{5}+\frac{ 3 }{ 2 }\]

Answer 5

E.\[x=-\sqrt{5}+\frac{ 3 }{ 2 }\]

Answer 6

F.\[x=-\sqrt{4}-3\]

Answer 7

What do you think?

Answer 8

i dont get it

Answer 9

http://www.wolframalpha.com/input/?i=x%5E2-6x%2B9%3D11

Answer 10

can someone check my answer it the link

Answer 11

\[4x^2-12x+9=5 \]\[(3-2 x)^2 = 5\]\[(2 x-3)^2 = 5\]Then take the square root!

Answer 12

is the link trying to say \[x=\sqrt{11}+3\]

Answer 13

$$\tt
\tt
\begin{align*} \\
4x^2-12x+9=5\\
4x^2-12x+4=0\\
4(x^2-3x+1)=0)\\
(x^2-3x+1)=0)\\
x=\frac{3\pm\sqrt{9-4}}{2}\\
x=\frac{3\pm\sqrt{5}}{2}\\
\end{align*}$$

Answer 14

YUP! A and C

Answer 15

and \[x=-\sqrt{11}+3\]

Answer 16

No. It is not!

Answer 17

Look at what @ybarrap said!