Mathematics
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OpenStudy (loser66):
find eigenvalue of \[\left(\begin{matrix}-2i&-4\\1&-2i\end{matrix}\right)\]
Please, help
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OpenStudy (anonymous):
Don't worry we will help
OpenStudy (loser66):
Thanks
OpenStudy (anonymous):
Is there any answer choices?
OpenStudy (loser66):
nope,
OpenStudy (anonymous):
Can you write it how you see it without using equation
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OpenStudy (loser66):
ok, got what you mean. I have problem as
\[x'=\left(\begin{matrix}-1&-4\\1&-1\end{matrix}\right)x\]
OpenStudy (anonymous):
Give me one second
OpenStudy (loser66):
oh, I got it now. I am sorry for bothering and thanks for response. XD
OpenStudy (anonymous):
Are you sure?
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OpenStudy (anonymous):
Also where was the question from?
OpenStudy (loser66):
nope, I am not sure just this part. I took linear last Spring and afraid of this part only. the rest is ok, I can handle it.
OpenStudy (anonymous):
Let me keep trying
OpenStudy (anonymous):
What did you get?
OpenStudy (loser66):
I got eigenvector \([2i,b]^T\)
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OpenStudy (anonymous):
Hmm
OpenStudy (loser66):
what do you mean by "Hhm"?
OpenStudy (anonymous):
Just checking my answers
OpenStudy (loser66):
oh, I am sorry, it's \([2i, 1]\) not b, hihihi
OpenStudy (anonymous):
Correct
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OpenStudy (anonymous):
Good job!
OpenStudy (loser66):
hehehe...thanks for being here with me.
OpenStudy (anonymous):
Yeah no problem!
OpenStudy (loser66):
hey, I have another question
OpenStudy (loser66):
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