Question

probability scorers i need your help here please...

Of the 16 members of President Barak Obama’s first Cabinet, 4 were women. Suppose the president randomly selected 4 advisors from the cabinet for a meeting. Find the probability that the group of 4 would be composed as follows: (Hints: first define the random variable X. Then write the objective of each question in terms of X.)

a) 3 women and 1 man;
B. All men;
c. At least one woman

Answer 1

Hint for part a: Your probability will be expressed as a fraction. The numerator is the product of (all the possible ways to select 3 women from a group of 4) times (all the possible ways to select 1 man from a group of 12). The denominator is all the ways to select a group of 4 from 16.

Answer 2

please write it out and let me see..

Answer 3

How about you write it out and let me see your work.

Answer 4

erm dont really have a clear idea..

Answer 5

If you were studying your class material, you would have a very good idea. You shouldn't use Openstudy as a way for others to do your work. This is your problem, not mine. You should be able to do something here.

Answer 6

with this question can i use combination formula to solve

Answer 7

Yes, but under the restrictions suggested in my hint. Each of the components from that hint are combinations. 2 in the numerator and one in the denominator.

Answer 8

erm give me some few seconds and let me come up with some solution so u verify

Answer 9

Sounds good.

Answer 10

i had a decimal for the women part

Answer 11

0.0015

Answer 12

I see a number with no work shown, so I'm outta here. I don't help people who don't show their work. I don't help people looking only for answers. I help only those who are honestly trying to solve their own problems.

Answer 13

oh ok...i think u need to take it easy..after all some of us are here to learn..other than that we wouldnt be..

Answer 14

rmula and i \[nCr = n!\div(n-r)!r!\]