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HELP!!!!!! A volume of 18.0 L contains a mixture of 0.250 mole N2 , 0.250 mole O2 , and an unknown quantity of He. The temperature of the mixture is 0 ∘C , and the total pressure is 1.00 atm . How many grams of helium are present in the gas mixture?
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PV=nRT n=0.25+0.25+x x=moles of helium -> convert to grams after
so whats the answer? @aaronq
lol that's for you to compute
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