Question

Write the expression for the slope of a line whose equation is Ax+By+C=0?

Answer 1

Slope is normally given in the equation y = mx + b [WHERE m is slope okay?]
[AND y CO-EFF. IS ZERO]
So in this equation Ax + By + c = 0
or By = - Ax - c
And then divide the LHS n RHS by B
So what do YOU think m or the slope will be here?
Refer to the equation y = mx+ b!
Try! :)

Answer 2

so its y=(-Ax-c/B) ?

Answer 3

Yeah kinda!
y = -Ax/B - c/B
So in the equation y = mx + c
m is the co-efficient of x and the slope!
What do YOU think the slope will be here? :D

Answer 4

@Ailee

Answer 5

o-o errr I thought it would just be -Ax/b. sorry im confused D:

Answer 6

CHILLOUT!! :D
Good try though! [I wasn't have as good as you when I WAS LEARNING THIS]
-Ax/B is the whole thing [-A/B is the coefficient]
That means that -A/B is the constant term getting me?
So here the slop of the equation Ax + By + c = 0
Should be??
m = -A/B
Because it is the co-efficient of x
written in the form = y = -Ax/B - c/B
Understood?? :D

Answer 7

YES!!:D i get that part but then what to do after that step?

Answer 8

Say we have the equation 2x - 3y = 6 okay?
Try finnding the slope (m) of that!

Answer 9

the slope is 2/3x

Answer 10

Good Good!
But you see there is only one problem the slope is always the constant term
Not including the variable so the slop would be ?
2/3!! :D [YIPPEEE]
Did you get this question now? :)

Answer 11

OOHHH SO if im not mistaken it should be y=-A/B - C/B ??? O-O

Answer 12

No Ailee [LISTEN TO ME CAREFULLY]
See y = mx + b --> IS THE STANDARD FORM OF 'ANY' LINE [Where m is slope]
So in our case
By = -Ax - c
or y = -Ax/B - c/B
\[y = mx + b\]
In our case though
\[y = -Ax/B - c/B\]
So in our case our slope will be?
-A/B because it is like the 'm' in the standard line equation!
Getting me?
Ask me if you have any question. :D

Answer 13

so the answer is -A/B because its the slope in the equation ?

Answer 14

and they are also only looking for the slope

Answer 15

YES!! :)
YOU ARE RIGHT!! :D

Answer 16

OMG YAY!!! :DDDDDDDDDDDDDDDDDDD

Answer 17

YOUR SO COOL :3

Answer 18

Thank you! :D :)
Have fun!! :D

Answer 19

If you could help, I have another question I don't know how to start:
write the standard form form of the equation of the line that is parallel to the graph of the given equation and passes through the point with the given 4x-9y= -23;(12,-15)

Answer 20

Hold on for one sec!

Answer 21

Ok now see

Answer 22

Both the lines obviously have same gradient only and only because they are parrllel.
[FIND THE SLOPE LIKE I SHOWED YOU]
Thus, if they are parrallel slope of the parrallel line passes through (12,-15) and has slope 4/9
Now there is something known as the point slope equation of the line!
That states: (y-y1) = m(x-x1)
So we have
(x1,y1) = (12,-15)
And m = 4/9
Put it in the line equation and then get the equation of the parallel line!! :D
Understood?? :)

Answer 23

ok, thanks C;

Answer 24

Medal me plz?

Answer 25

:/