Question

Please Help! Fan + Medal!

Posted Below!

Answer 1

@Psymon @Nurali

Answer 2

Ok to solve this

Answer 3

Do you mind actually writing the question?

Answer 4

That would help me explain it

Answer 5

Okay so look!
In this question
You have a the point of tht perpendicular and you have a line equation!

Answer 6

Now if 2 lines are perpendicular there sloper m1 and m2
Vary like this m1 * m2 = -1 alrgiht?

Answer 7

So the line that is given to us says the equation of the line is y = 2x - 1
So the slope in this equation according to the standard line equation y = mx + b
m1 = 2!! Getting me?

Answer 8

So for a line perpendicular to it the slope of that would be? m1 * m2 = -1
2 * m2 = -1

Thus the equation of the line perpendicular = m2 = -1/2

Answer 9

So you have a point on the perpendicular line and you have the slope!

Answer 10

It kinda looks like this!

Answer 11

So according to the point-slope form of a line = (y-y1) = m(x-x1)
Thus
(x1,y1) = (-2,-2)
And m = -1/2
Put those values in the equationa dnyou'll ge thte Answer!!
Okay?
Understood the question? :)

Answer 12

the line Y = 2X - 1 has the gradient 2

from Y = MX + C where M is the gradient

to find the gradient of a perpendicular line = -1/M

so the perpendicular gradient = -1/2

so the equation is Y = (-1/2) X + C

to find C, enter the value for Y and for X from any point on this line.

the point (-2,-2) is said to be on this line so X = -2 and Y = -2

then Y = (-1/2) X + C
-2 = (-1/2)x (-2) + C
so C = -3

therefore the equation of the perpendicular line is

Y = -1/2X - 3

Answer 13

Did you understand?

Answer 14

Point-slope formula:
\[y-y _{1}=m(x-x _{1})\]
where
\[(x_{1},y _{1}) = (-2,-2)\]
and
\[m=\frac{ -1 }{ slope of perpendicular line }=\frac{ -1 }{ 2 }\]
Fill in all the variables, simplifly and there's your equation.

Pretty much what they said but I tried to make it simpler with less clutter. Hope it helps.