Integrate this
\[\Huge \int\limits_{}^{} \frac{\sin x}{\sin x+\cos x}\]
I tried converting sinx to 2tanx/2 / (1+tan^2 x/2) and cosx to 1-tan^2x/2 / 1+tan^2 x/2 but it lead me nowhere..need a hint :(
@amistre64 @dan815 @ganeshie8 @yrelhan4
let \[A=\int \frac{\sin x}{\sin x + \cos x}dx\\B=\int\frac{\cos x}{\sin x + \cos x}dx\] evaluate B+A and B-A
\[\large B+A=\int\frac{\sin x + \cos x}{\sin x + \cos x}dx = x\] \[\large B-A=\int\frac{\cos x - \sin x}{\sin x + \cos x}dx =\ln|\sin x + \cos x|\] subtract the two equations
\[\frac{ 1 }{ 2 } \int\limits_{}^{}\frac{ \sin(x)+\cos(x)+\sin(x)-\cos(x) }{ \sin(x)+\cos(x) }=\frac{ 1 }{ 2 } \int\limits_{}^{}1+\frac{ \sin(x)-\cos(x) }{ \sin(x)+\cos(x) }=\frac{ 1 }{ 2 }(x-\ln(\sin(x)+\cos(x)))\]
sorry @sirm3d I did not see your reply
I don't even know where I'm going with this.. @sirm3d 's looks so blissfully elegant :D
that was nice @sirm3d
thank you. but credit goes to Schaum's Outline Series. hehehe.
thanks!
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