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(2x)^-6 Simplify. Use positive exponents only.
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What does it mean by the "use positive exponents only"? When I get my answer it looks like 1/64(x^-6)
1/64x^6
How come it isn't -6?
you multiplied wrong i think.
\[\large (2x)^{-6} = \frac{1}{(2x)^6}\] \[\large (2x)^{-6} = \frac{1}{2^6*x^6}\] \[\large (2x)^{-6} = \frac{1}{64x^6}\]
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I'm using the idea that \[\large x^{-k} = \frac{1}{x^k}\]
Okay that makes more sense. Thank you!
yw
would it be 1/64(x^6)
It is \[\large \frac{1}{64x^6}\]
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this might be a stupid question but cant the exponent be distributed later on to the 64?
it already has "distributed" that's how (2x)^6 turned into 64x^6
when you have 64x^6, the exponent of 6 only applies to the x
gotcha, thank ya
yw
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