Question

see attachment (@jim_thompson5910 I know you helped me the last time but this one is different)

Answer 1

\[(5+2\sqrt{2})(8-3\sqrt{2})\]

Answer 2

I can help you here

Answer 3

Do you know how to start it?

Answer 4

well normly I would distribute but I don't think you can do that on this one?!?

Answer 5

yes you certainly can :)

Answer 6

how?

Answer 7

you would have

(5*(-3√2)) + (5*8) + (2√2 *8) - (2√2 *3√2)

Answer 8

Make sense so far?

Answer 9

or -(5*3√2) + (5*8) + (2√2 *8) - (2√2 *3√2)

Answer 10

The second one makes more since and sorry it took so long im doing laundary to?!!? lol

Answer 11

haha that's ok, so do you know what to do from here?

Answer 12

do I add all the numbers outside the square

Answer 13

@snowskimwake

Answer 14

after you multiply. The next step would be to multiply inside the parenthesis

Answer 15

This is what I got it to @snowskimwake \[(15\sqrt{2})+(40)+2\sqrt{2}*8)-(2\sqrt{2}*3\sqrt{2})\]
now im stuck

Answer 16

keep going though, you can multiple 2√2 * 8

Answer 17

its just 16√2

Answer 18

o okay so the next on would be \[6\sqrt{2}\]

Answer 19

no, you have to multiple the inside too

Answer 20

so √2 times √2 = √4

Answer 21

you would end up with 6√4

Answer 22

and √4 is just 2, so then 6(2) which is 12

Answer 23

I thought you leave the number inside the square alone if it is the same

Answer 24

also you missed a sign, 15√2 should be negative

Answer 25

only if you are adding or subtracting

Answer 26

if you are multiplying or dividing you do the same with the inside

Answer 27

o okay so it you * you will change it?

Answer 28

yeah, so you would have

-15√2+40+16√2−12

Answer 29

then combine like terms and you got it! :D

Answer 30

then it would be \[29+\sqrt{2}\]

Answer 31

28 but yes otherwise you got it

Answer 32

okay sorry I made a addition mistake thank you!