Question

secx+tanx=cosx/1−sinx

Prove this.

Answer 1

secx + tanx
= 1/cosx + sinx/cosx
= (1+sinx)/cosx
= Multiply denominator and the numerator by (1-sinx)
It becomes
= (1-sin^2x)/cosx(1-sinx)
= (cos^2x/cosx(1-sinx)
= cosx/1 - sinx
= RHS
Understand? :)

Answer 2

Ah yes, that was it! I'll have to remeber that