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Mathematics 16 Online
OpenStudy (anonymous):

If the volumes of two similar figures are 27 mm^3 and 1331 mm^3. If the surface area of the smaller figure is 18mm^2, what is the surface area of the larger figure

OpenStudy (anonymous):

any ideas?

OpenStudy (jdoe0001):

what do you think is the scale factor or ratio for the volumes?

OpenStudy (jdoe0001):

notice that \(\bf 27 = 3^3\\ 1331 = 11^3\)

OpenStudy (anonymous):

makes sense

OpenStudy (jdoe0001):

thus we can say that, the ratio or scale factor for the volumes, corresponds to the ratio of the surface areas thus we can say that \(\bf \cfrac{27}{1331} \implies \cfrac{3^3}{11^3} \implies \textit{ ratio will be } \cfrac{3}{11}\\ \textit{thus we could say that }\\ \cfrac{3^2}{11^2}=\cfrac{18}{x}\)

OpenStudy (anonymous):

so now we have to find what x is?

OpenStudy (jdoe0001):

yes, "x" is the surface area of the bigger similar figure, which corresponds to 18 on the smaller figure

OpenStudy (anonymous):

what is the next step

OpenStudy (jdoe0001):

the next step is be happy, buy cheetos and enjoy :)

OpenStudy (jdoe0001):

there's no next step, "x" is what you're required to find, the area of the bigger similar figure

OpenStudy (anonymous):

|dw:1376603096000:dw|

OpenStudy (jdoe0001):

?

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